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Flatten Nested List Iterator

Description

https://leetcode.com/problems/flatten-nested-list-iterator/description/

Solution

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/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* class NestedInteger {
* public:
* // Return true if this NestedInteger holds a single integer, rather than a nested list.
* bool isInteger() const;
*
* // Return the single integer that this NestedInteger holds, if it holds a single integer
* // The result is undefined if this NestedInteger holds a nested list
* int getInteger() const;
*
* // Return the nested list that this NestedInteger holds, if it holds a nested list
* // The result is undefined if this NestedInteger holds a single integer
* const vector<NestedInteger> &getList() const;
* };
*/
class NestedIterator {
public:
NestedIterator(vector<NestedInteger>& nestedList) {
this->index = 0;
this->list = new vector<int>();
this->parse(nestedList);
this->length = this->list->size();
}

void parse(vector<NestedInteger>& nestedList) {
for(int i = 0; i < nestedList.size(); i++){
if(nestedList[i].isInteger() == true) this->list->push_back(nestedList[i].getInteger());
else this->parse(nestedList[i].getList());
}
}

int next() {
int ret = (*this->list)[index];
this->index += 1;
return ret;
}

bool hasNext() {
return this->index < this->length;
}
private:
vector<int>* list;
int index;
int length;
};

/**
* Your NestedIterator object will be instantiated and called as such:
* NestedIterator i(nestedList);
* while (i.hasNext()) cout << i.next();
*/