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Design Tic-Tac-Toe

Description

Design a Tic-tac-toe game that is played between two players on a n x n grid.

You may assume the following rules:

  1. A move is guaranteed to be valid and is placed on an empty block.
  2. Once a winning condition is reached, no more moves is allowed.
  3. A player who succeeds in placing n of their marks in a horizontal, vertical, or diagonal row wins the game.

Example:

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Given n = 3, assume that player 1 is "X" and player 2 is "O" in the board.

TicTacToe toe = new TicTacToe(3);

toe.move(0, 0, 1); -> Returns 0 (no one wins)
|X| | |
| | | | // Player 1 makes a move at (0, 0).
| | | |

toe.move(0, 2, 2); -> Returns 0 (no one wins)
|X| |O|
| | | | // Player 2 makes a move at (0, 2).
| | | |

toe.move(2, 2, 1); -> Returns 0 (no one wins)
|X| |O|
| | | | // Player 1 makes a move at (2, 2).
| | |X|

toe.move(1, 1, 2); -> Returns 0 (no one wins)
|X| |O|
| |O| | // Player 2 makes a move at (1, 1).
| | |X|

toe.move(2, 0, 1); -> Returns 0 (no one wins)
|X| |O|
| |O| | // Player 1 makes a move at (2, 0).
|X| |X|

toe.move(1, 0, 2); -> Returns 0 (no one wins)
|X| |O|
|O|O| | // Player 2 makes a move at (1, 0).
|X| |X|

toe.move(2, 1, 1); -> Returns 1 (player 1 wins)
|X| |O|
|O|O| | // Player 1 makes a move at (2, 1).
|X|X|X|

Follow up:
Could you do better than O(n2) per move() operation?

Solution

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class TicTacToe {
private:
vector<vector<int>> grid;
vector<int> rowSum;
vector<int> rowProduct;
vector<int> colSum;
vector<int> colProduct;
vector<int> diagonalSum;
vector<int> diagonalProduct;
int size;
vector<int> playerProduct;
public:
/** Initialize your data structure here. */
TicTacToe(int n) {
vector<vector<int>> newGrid(n, vector<int>(n, 0));
grid = newGrid;

//Target
playerProduct.push_back(1);
playerProduct.push_back(1 << n);

//Sum
rowSum.resize(n);
colSum.resize(n);
diagonalSum.resize(2);

//Product
for (int i = 0; i < n; ++i) {
rowProduct.push_back(1);
colProduct.push_back(1);
}
diagonalProduct.push_back(1);
diagonalProduct.push_back(1);
size = n;
}

/** Player {player} makes a move at ({row}, {col}).
@param row The row of the board.
@param col The column of the board.
@param player The player, can be either 1 or 2.
@return The current winning condition, can be either:
0: No one wins.
1: Player 1 wins.
2: Player 2 wins. */
int move(int row, int col, int player) {
grid[row][col] = player;


rowSum[row] += player;
rowProduct[row] *= player;

colSum[col] += player;
colProduct[col] *= player;

if (int pos = diagonal(row, col)) {
if (pos == 3) {
diagonalSum[0] += player;
diagonalSum[1] += player;
diagonalProduct[0] *= player;
diagonalProduct[1] *= player;
}else {
diagonalSum[pos - 1] += player;
diagonalProduct[pos - 1] *= player;
}


if ( (diagonalSum[0] == size * player
&& diagonalProduct[0] == playerProduct[player - 1])
|| (diagonalSum[1] == size * player
&& diagonalProduct[1] == playerProduct[player - 1])
)
return player;
}

if ( (rowSum[row] == size * player && rowProduct[row] == playerProduct[player - 1])
|| (colSum[col] == size * player && colProduct[col] == playerProduct[player - 1]) )
return player;

return 0;
}

int diagonal(int row, int col) {
if (size % 2 && row == size / 2 && col == size / 2) return 3;
if (row == col) return 2;
if (row + col == size - 1) return 1;
return 0;
}
};

/**
* Your TicTacToe object will be instantiated and called as such:
* TicTacToe obj = new TicTacToe(n);
* int param_1 = obj.move(row,col,player);
*/